Latest Dec 29, 2023 Real 1z0-071 Exam Dumps Questions Valid 1z0-071 Dumps PDF
Oracle 1z0-071 Exam Dumps - PDF Questions and Testing Engine
NEW QUESTION # 110
View the Exhibit and examine the details of PRODUCT_INFORMATIONtable.
You have the requirement to display PRODUCT_NAMEfrom the table where the CATEGORY_IDcolumn has values 12or 13, and the SUPPLIER_IDcolumn has the value 102088. You executed the following SQL statement:
SELECT product_name
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088; Which statement is true regarding the execution of the query?
- A. It would not execute because the same column has been used in both sides of the ANDlogical operator to form the condition.
- B. It would not execute because the entire WHEREclause condition is not enclosed within the parentheses.
- C. It would execute but the output would return no rows.
- D. It would execute and the output would display the desired result.
Answer: C
NEW QUESTION # 111
Examine this SQL statement:
SELECT cust_id, cust_last_name "Last Name
FROM customers
WHERE countryid=10
UNION
SELECT custid CUSTNO, cust_last_name
FROM customers
WHERE countryid=30
Identify three ORDER BY clauses, any one of which can complete the query successfully.
- A. ORDERBY2, 1
- B. ORDER BY "Last Name"
- C. ORDER BY"CUST NO"
- D. ORDER BY CUSTNO
- E. ORDER BY 2, cust_id
Answer: A,B,E
NEW QUESTION # 112
Examine the commands used to create DEPARTMENT_DETAILSand COURSE_DETAILS:
You want to generate a report that shows all course IDs irrespective of whether they have corresponding department IDs or not but no department IDs if they do not have any courses.
Which SQL statement must you use?
SELECT course_id, department_id, FROM department_details d RIGHT OUTER JOIN
- A. department_details d ON (c.department_id=d. department_id)
SELECT c.course_id, d.department_id FROM course_details c FULL OUTER JOIN - B. department_details d ON (c.department_id<>d. department_id)
- C. course_details c USING (department_id)
SELECT c.course_id, d.department_id FROM course_details c RIGHT OUTER JOIN - D. .department_details d ON (c.depatrment_id=d.department_id)
SELECT c.course_id, d.department_id FROM course_details c FULL OUTER JOIN
Answer: A
NEW QUESTION # 113
View the exhibit and examine the description of the DEPARTMENTSand EMPLOYEEStables.
The retrieve data for all the employees for their EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT NAME, the following SQL statement was written:
SELECT employee_id, first_name, department_name
FROM employees
NATURAL JOIN departments;
The desired output is not obtained after executing the above SQL statement. What could be the reason for this?
- A. The NATURAL JOINclause is missing the USINGclause.
- B. The table prefix is missing for the column names in the SELECTclause.
- C. The EMPLOYEESand DEPARTMENTStables have more than one column with the same column name and data type.
- D. The DEPARTMENTStable is not used before the EMPLOYEEStable in the FROMclause.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Natural join needs only one column to be the same in each table. The EMPLOYEESand DEPARTMENTS tables have two columns that are the same (Department_ID and Manager_ID)
NEW QUESTION # 114
Which three statements are true regarding group functions? (Choose three.)
- A. They can be used along with the single-row function in the SELECT clause of a SQL statement.
- B. They can be used on only one column in the SELECT clause of a SQL statement.
- C. They can be used only with a SQL statement that has the GROUP BY clause.
- D. They can be passed as an argument to another group function.
- E. They can be used on columns or expressions.
Answer: A,D,E
NEW QUESTION # 115
Which two are true about queries using set operators (UNION, UNION ALL, INTERSECT and MINUS?
- A. The must be an equal number of columns In each select list.
- B. The name off each column in the first Select list must match the name of the corresponding column In each subsequent select list.
- C. The FOR update clause cannot be specified.
- D. Each select statement In the query can have an order by clause.
- E. None of the set operators can be used when selecting CLOB columns.
Answer: A,C
NEW QUESTION # 116
Which task can be performed by using a single Data Manipulation Language (DML) statement?
- A. removing all data only from a single column on which a primary key constraint is defined
- B. adding a column constraint while inserting a row into a table
- C. adding a column with a default value while inserting a row into a table
- D. removing all data only from a single column on which a unique constraint is defined
Answer: D
NEW QUESTION # 117
View the exhibit and examine the description of the PRODUCT_INFORMATION table.
Which SQL statement would retrieve from the table the number of products having LIST_PRICE as NULL?
- A. SELECT COUNT (list_price)FROM product_informationWHERE list_price is NULL
- B. SELECT COUNT (list_price)FROM product_informationWHERE list_price i= NULL
- C. SELECT COUNT (DISTINCT list_price)FROM product_informationWHERE list_price is NULL
- D. SELECT COUNT (NVL(list_price, 0))FROM product_informationWHERE list_price is NULL
Answer: D
NEW QUESTION # 118
Which three are true about the MERGEstatement? (Choose three.)
- A. It can use views to produce source rows.
- B. It can use subqueries to produce source rows.
- C. It can update the same row of the target table multiple times.
- D. It can combine rows from multiple tables conditionally to insert into a single table.
- E. It can update, insert, or delete rows conditionally in multiple tables.
- F. It can merge rows only from tables.
Answer: A,B,E
Explanation:
Explanation/Reference: https://www.oracletutorial.com/oracle-basics/oracle-merge/
NEW QUESTION # 119
These are the steps for a correlated subquery, listed in random order:
* The WHERE clause of the outer query is evaluated.
* A candidate row is fetched from the table specified in the outer query.
* This is repeated for the subsequent rows of the table, until all the rows are processed.
* Rows are returned by the inner query, after being evaluated with the value from the candidate row in the outer query.
Which is the correct sequence in which the Oracle server evaluates a correlated subquery?
- A. 4, 1, 2, 3
- B. 4, 2, 1, 3
- C. 2, 1, 4, 3
- D. 2, 4, 1, 3
Answer: D
Explanation:
Explanation
http://rajanimohanty.blogspot.co.uk/2014/01/correlated-subquery.html
NEW QUESTION # 120
Examine the contents of the EMP table:
What is the result?
- A. It will return the five employees earning the highest salaries. In descending order.
- B. It will return the six employees earning the lowest salaries. In ascending order.
- C. It will return the six employees earning the highest salaries. In descending order.
- D. It will return the five employee's earning the lowest salaries. In ascending order.
Answer: D
NEW QUESTION # 121
View the exhibit for the structure of the STUDENT and FACULTY tables.
You need to display the faculty name followed by the number of students handled by the faculty at the base location.
Examine the following two SQL statements:
Statement 1
SQL>SELECT faculty_name, COUNT(student_id)
FROM student JOIN faculty
USING (faculty_id, location_id)
GROUP BY faculty_name;
Statement 2
SQL>SELECT faculty_name, COUNT(student_id)
FROM student NATURAL JOIN faculty
GROUP BY faculty_name;
Which statement is true regarding the outcome?
- A. Both statements 1 and 2 execute successfully and give different results.
- B. Only statement 2 executes successfully and gives the required result.
- C. Only statement 1 executes successfully and gives the required result.
- D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: C
NEW QUESTION # 122
View the Exhibit and examine the structure of CUSTOMERS table.
Using the CUSTOMERS table, you need to generate a report that shows an increase in the credit limit by 15% for all customers. Customers whose credit limit has not been entered should have the message "Not Available" displayed.
Which SQL statement would produce the required result?
- A. SELECT NVL(cust_credit_limit), 'Not Available') "NEW CREDIT"FROM customers;
- B. SELECT TO_CHAR (NVL(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"FROM customers;
- C. SELECT NVL(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"FROM customers;
- D. SELECT NVL (TO CHAR(cust_credit_limit * .15), 'Not Available') "NEW CREDIT"FROM customers;
Answer: D
NEW QUESTION # 123
View the exhibit and examine the structure and data in the invoice table. (Choose two.)
Which two SQL statements would execute successfully?
- A. SELECT MAX(inv_date), MIN(cust_id) FROM invoice
- B. SELECT AVG(inv_date) FROM invoice
- C. SELECT MAX(AVG(SYSDATE -inv_date)) FROM invoice
- D. SELECT AVG( inv_date -SYSDATE), AVG(inv_amt) FROM invoice
Answer: A,D
NEW QUESTION # 124
which is true about the round,truncate and mod functions>?
- A. TRUNC(MOD(25,3),-1) IS INVALID.
- B. ROUND(MOD(25,3),-1) AND TRUNC(MOD(25,3),-1) ARE BOTH VALID AND GIVE THE SAME RESULT.
- C. ROUND(MOD(25,3),-1) IS INVALID
- D. ROUND(MOD(25,3),-1) AND TRUNC(MOD(25,3),-1) ARE BOTH VALID AND GIVE THE DIFFERENT RESULTS.
Answer: B
NEW QUESTION # 125
View the Exhibit and examine the structure of the CUSTOMERS and CUST_HISTORY tables.
The CUSTOMERS table contains the current location of all currently active customers. The CUST_HISTORY table stores historical details relating to any changes in the location of all current as well as previous customers who are no longer active with the company.
You need to find those customers who have never changed their address.
Which SET operator would you use to get the required output?
- A. INTERSECT
- B. UNION
- C. UNION ALL
- D. MINUS
Answer: D
NEW QUESTION # 126
You need to list the employees in DEPARTMENT_ID20 days in a single row, ordered by HIRE_DATE.
Examine the sample output:
Which query will provide the required output?
SELECT LISTAGG(last_name)
- A. WITHIN GROUP ORDER BY (hire_date) "Emp_list", MIN(hire_date) "Earliest" FROM employees WHERE department_id = 30; SELECT LISTAGG(last_name, '; ') "Emp_list", MIN(hire_date) "Earliest"
- B. FROM employees
WHERE department_id = 30;
ORDER BY (hire_date); - C. WITHIN GROUP ORDER BY (hire_date) "Emp_list", MIN(hire_date) "Earliest" FROM employees WHERE department_id = 30; SELECT LISTAGG(last_name, '; ')
- D. FROM employees
WHERE department_id = 30;
WITHIN GROUP ORDER BY (hire_date);
SELECT LISTAGG(last_name, '; ') "Emp_list", MIN(hire_date) "Earliest"
Answer: A
NEW QUESTION # 127
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