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WGU Foundations of Programming (Python) - E010 JIV1 : Foundations-of-Programming-Python
- Exam Code: Foundations-of-Programming-Python
- Exam Name: Foundations of Programming (Python) - E010 JIV1
- Updated: Oct 06, 2026 Q & A: 62 Questions and Answers
About Pass4guide WGU Foundations-of-Programming-Python Exam
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WGU Foundations-of-Programming-Python Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Functions and Modularity | - Modules and imports - Function definition and scope |
| File Handling and Exceptions | - Exception handling (try/except) - Reading and writing files |
| Data Structures | - Basic data manipulation - Lists, tuples, dictionaries |
| Python Programming Fundamentals | - Variables and data types - Operators and expressions - Syntax and basic structure |
| Control Flow | - Loops (for, while) - Conditional statements (if / elif / else) |
| Introduction to Object-Oriented Programming | - Classes and objects - Basic OOP concepts |
| Debugging and Testing Basics | - Error identification and correction - Basic testing concepts |
WGU Foundations of Programming (Python) - E010 JIV1 Sample Questions:
Question #1
What must a developer do to run Python code written in a text editor?
- A. Convert the code to machine language first.
- B. Press a run button within the editor.
- C. Upload the code to a web server.
- D. Save the file and use a Python interpreter.
Correct Answer: D 🗳️
Explanation: Only visible for Pass4guide members. You can sign-up / login (it's free).
Question #2
Write a complete function password_strength(password) that returns " Strong " if the password is at least 8 characters long and contains both letters and numbers, " Weak " otherwise.
For example, password_strength( " abc123def " ) should return " Strong " .
def password_strength(password):
# TODO: Return " Strong " or " Weak " based on password criteria
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
# TODO: Add your return logic here based on has_letter and has_number
pass
Correct Answer:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: First, check the password length using len(password).
Step 2: If the password has fewer than 8 characters, return " Weak " immediately.
Step 3: Create two Boolean variables: has_letter and has_number.
Step 4: Loop through each character in the password.
Step 5: Use .isalpha() to check for letters and .isdigit() to check for numbers.
Step 6: If the password contains both at least one letter and at least one number, return " Strong " .
Step 7: Otherwise, return " Weak " .
Correct code:
def password_strength(password):
if len(password) < 8:
return " Weak "
has_letter = False
has_number = False
for char in password:
if char.isalpha():
has_letter = True
elif char.isdigit():
has_number = True
if has_letter and has_number:
return " Strong "
else:
return " Weak "
Example:
print(password_strength( " abc123def " ))
print(password_strength( " abcdefgh " ))
print(password_strength( " 12345678 " ))
Output:
Strong
Weak
Weak
Question #3
Modify the function greet_with_default(name) by adding a default value of " World " to the name parameter so it can be called with or without an argument.
def greet_with_default(name):
# TODO: Add a default value of " World " to the name parameter
return " Hello " + name
Correct Answer:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: A default parameter value allows a function to be called even when no argument is provided.
Step 2: The default value should be added in the function header.
Step 3: The parameter name should have the default value " World " .
Correct code:
def greet_with_default(name= " World " ):
return " Hello " + name
Example:
print(greet_with_default())
print(greet_with_default( " Alice " ))
Output:
Hello World
Hello Alice
Question #4
How can the first four characters be extracted from the string ' computer ' ?
- A. ' computer ' [1:5]
- B. ' computer ' [0:3]
- C. ' computer ' [0:4]
- D. ' computer ' [1:4]
Correct Answer: C 🗳️
Explanation: Only visible for Pass4guide members. You can sign-up / login (it's free).
Question #5
Fix the off-by-one error in this function that should return the first 3 characters of a string.
def first_three(text):
return text[0:2]
Correct Answer:
See the Step by Step Solution below in Explanation.
Explanation:
Step 1: Python string slicing uses this format:
text[start:stop]
Step 2: The start index is included.
Step 3: The stop index is excluded.
Step 4: To return the first 3 characters, start at index 0 and stop at index 3.
Correct code:
def first_three(text):
return text[0:3]
Simplified correct code:
def first_three(text):
return text[:3]
Example:
print(first_three( " Python " ))
Output:
Pyt
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